树莓派从 DHT11 温度湿度传感器读取数据

时序图参考厂家说明书:DHT11数字湿温度传感器的原理和应用范例

四个阵脚连接:VCC接3.3伏电源,Dout接GPIO口,我接的是物理12针脚,NC留空,GND接地。

波折1:电阻被错接进了VCC,于是看了无数遍时序图,改了无数遍的驱动无论怎么改都是读不出数据。

波折2:偶然看了网上的DHT11上拉电阻电路图才发现错误,于是果断去掉电阻。但为了显示传感器工作正常在电源和VCC间接了个发光二极管进去,数据倒是读出来了,但各种错误。(原因不明)

去掉了电阻,去掉了led,优化了写的python,读数正常。再一次赞一个python。

写DHT11的驱动需要注意时序之间很紧密,python执行任何程序都要花费时间,在获取时序时需要注意所写调试用的代码也是占用时序的,在这一点上也走了一点弯路。

# -*- coding: utf-8 -*- “”” Created on Sun Jan 26 14:24:43 2014 @author: pi “”” import RPi.GPIO as gpio import time gpio.setwarnings(False) gpio.setmode(gpio.BOARD) time.sleep(1) data=[] def delay(i): #20*i usdelay a=0 for j in range(i): a+1 j=0 #start work gpio.setup(12,gpio.OUT) #gpio.output(12,gpio.HIGH) #delay(10) gpio.output(12,gpio.LOW) time.sleep(0.02) gpio.output(12,gpio.HIGH) i=1 i=1 #wait to response gpio.setup(12,gpio.IN) while gpio.input(12)==1: continue while gpio.input(12)==0: continue while gpio.input(12)==1: continue #get data while j<40: k=0 while gpio.input(12)==0: continue while gpio.input(12)==1: k+=1 if k>100:break if k<3: data.append(0) else: data.append(1) j+=1 print "Sensor is working" #get temperature humidity_bit=data[0:8] humidity_point_bit=data[8:16] temperature_bit=data[16:24] temperature_point_bit=data[24:32] check_bit=data[32:40] humidity=0 humidity_point=0 temperature=0 temperature_point=0 check=0 for i in range(8): humidity+=humidity_bit[i]*2**(7-i) humidity_point+=humidity_point_bit[i]*2**(7-i) temperature+=temperature_bit[i]*2**(7-i) temperature_point+=temperature_point_bit[i]*2**(7-i) check+=check_bit[i]*2**(7-i) tmp=humidity+humidity_point+temperature+temperature_point if check==tmp: print "temperature is ", temperature,"wet is ",humidity,"%" else: print "something is worong the humidity,humidity_point,temperature,temperature_point,check is",humidity,humidity_point,temperature,temperature_point,check 测试python程序时间代码 # -*- coding: utf-8 -*- """ Created on Sun Jan 26 16:01:59 2014 @author: pi """ import time def delay(i): k=0 for j in range(i): k+=1 n=5000 j=0 a=time.time() i=1 c=time.time() d=c-a print d a=time.time() for i in range(n): j+=1 c=time.time() d=c-a print d a=time.time() delay(n) c=time.time() d=c-a print d via